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Simplifying c4 + -8c2 + 16 = 0 Reorder the terms: 16 + -8c2 + c4 = 0 Solving 16 + -8c2 + c4 = 0 Solving for variable 'c'. Factor a trinomial. (4 + -1c2)(4 + -1c2) = 0 Factor a difference between two squares. ((2 + c)(2 + -1c))(4 + -1c2) = 0 Factor a difference between two squares. ((2 + c)(2 + -1c))(2 + c)(2 + -1c) = 0Subproblem 1
Set the factor '(2 + c)' equal to zero and attempt to solve: Simplifying 2 + c = 0 Solving 2 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + c = 0 + -2 c = 0 + -2 Combine like terms: 0 + -2 = -2 c = -2 Simplifying c = -2Subproblem 2
Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2Subproblem 3
Set the factor '(2 + c)' equal to zero and attempt to solve: Simplifying 2 + c = 0 Solving 2 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + c = 0 + -2 c = 0 + -2 Combine like terms: 0 + -2 = -2 c = -2 Simplifying c = -2Subproblem 4
Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2Solution
c = {-2, 2, -2, 2}
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